If we add up terms n through n+10, then we get
(n+10)/2 (2a + (n+9)45) - (n-1)/2 (2a+(n-2)45) = 891
11a+495n = -1089
a+45n = -99
If we are adding up the first 11 terms, then a = -144 and
T28 = -144+27*45 = 1071
T45 = -144+44*45 = 1836
But, if we add up terms T5 through T15, then n=5, and a = -324 and
T28 = 891
T45 = 1656
Better tie down your conditions a bit better
the sum of 11terms of A.P is 891.find the 28th and 45th terms if the common difference is 45
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the sum of 11 terms of an a.p is 891 find the 28th and 45th terms if the common difference is 15
abcd is atrape zium in whibh ab 11 dc.\ab/=4 11cm.\dc/=9cm abc =68,\bb/=7.5cm calculate the area of the trapezium?
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The sum of 11 terms of an Ap is 891,find the 28th and 45th terms if the common difference is 15