the sum of 11 terms of an A.P is 891. find the 28th and 45th terms if the common difference is 15

Answer 1

Use you sum(n) terms formula
(11/2)(2a + 10d) = 891
but d = 15
(11/2)(2a + 150) = 891
11(2a + 150) = 1782
2a + 150 = 162

continue

once you have a, just use your formula
term(28) = a + 27d = ....
etc

Answer 2

show teh working

Answer 3

thanks

Answer 4

The sum of 11 term of an A. P is 891.Find the 28th and 45th term.If the common difference is 15

Answer 5

The sum of 11 term of an A.P is 891.find the 28 and 45 if the common different is 15

Answer 6

solving with Sum (n)term formulea.(11/2)(2a+10d)=891. but remember d=15 (11/2)(2a+150)=5.5(2a+150)=891. 11(2a+150)=1782 and 2a+150=162

Answer 7

How is the 28th term lower than the 11th term

Answer 8

show me the solving

Answer 9

the sum of 11 terms of an a.p is 891 find the 28 and 45 terms if the common difference ir 15

Answer 10

I don't understand please

Answer 11

Maths

Answer 12

I don't understand please

Answer 13

The first term of an AP is 891. Find the 25th and 45th term if the common difference is 15

Answer 14

the sum of 11th term of an A.p is 891 find the 28th and 42th if the common different is 15

Answer 15

Show complete workings

Answer 16

Sn=891