The student says that a ball dropped from a height of 3.0 meters would have less than 96 joules of kinetic energy when it hits the ground. Is she correct and why?

5 answers

To determine whether the student is correct, we can calculate the potential energy of the ball at the height of 3.0 meters. When the ball is dropped, its potential energy is converted into kinetic energy as it falls. The formula for gravitational potential energy (PE) is:

\[ PE = m \cdot g \cdot h \]

where:

  • \(m\) is the mass of the ball (in kilograms),
  • \(g\) is the acceleration due to gravity (approximately \(9.81 , \text{m/s}^2\)),
  • \(h\) is the height from which the ball is dropped (in meters).

Given that the height \(h = 3.0 , \text{m}\), we need to calculate the potential energy, which will be equal to the kinetic energy (KE) just before it hits the ground (assuming no air resistance).

Substituting in the values we have:

\[ PE = m \cdot 9.81 , \text{m/s}^2 \cdot 3.0 , \text{m} = 29.43m , \text{J} \]

The kinetic energy when the ball hits the ground will be equal to the potential energy at the height of 3.0 m:

\[ KE = PE = 29.43m , \text{J} \]

Now, to find out whether this energy is less than 96 joules, we can analyze the expression \(29.43m , \text{J}\):

  1. If \(m = 1 , \text{kg}\), then \(KE = 29.43 , \text{J}\).
  2. If \(m = 2 , \text{kg}\), then \(KE = 58.86 , \text{J}\).
  3. If \(m = 3 , \text{kg}\), then \(KE = 88.29 , \text{J}\).
  4. If \(m = 4 , \text{kg}\), then \(KE = 117.72 , \text{J}\).

From the calculations, we can see that for a mass of 3 kg or less, the kinetic energy is less than 96 joules. The kinetic energy will equal or exceed 96 joules when the mass exceeds approximately 3.26 kg (since \(29.43m \geq 96\) yields \(m \geq \frac{96}{29.43} \approx 3.26 , \text{kg}\)).

Thus, the student is correct, assuming the mass of the ball is 3 kg or less, the kinetic energy when it hits the ground will indeed be less than 96 joules. If the mass of the ball is greater than 3.26 kg, the kinetic energy would exceed 96 joules.

She is correct because the higher the ball is dropped from, the less kinetic energy it will have when it hits the ground.
She is correct because the higher the ball is dropped from, the greater kinetic energy it will have when it hits the ground.
She is incorrect because the higher the ball is dropped from, the greater kinetic energy it will have when it hits the ground.
She is incorrect because the higher the ball is dropped from, the less kinetic energy it will have when it hits the ground.

The correct reasoning is:

"She is incorrect because the higher the ball is dropped from, the greater kinetic energy it will have when it hits the ground."

As explained in the previous response, when a ball is dropped from a greater height, it has more gravitational potential energy, which is converted to kinetic energy as it falls. Therefore, a ball dropped from a height of 3.0 meters will have more kinetic energy when it hits the ground than a ball dropped from a lower height.

In fact, the potential energy (and thus the kinetic energy upon impact) increases proportional to the height from which it is dropped, assuming no energy losses (e.g., air resistance). So, the statement about the effect of height on kinetic energy is reversed: higher heights result in greater kinetic energy at the moment before hitting the ground.

you just said she was correct

I apologize for the confusion in my previous answer regarding the phrasing. To clarify:

The student is actually incorrect. The appropriate reasoning is:

"She is incorrect because the higher the ball is dropped from, the greater kinetic energy it will have when it hits the ground."

If an object (like the ball) is dropped from a higher position, it gains more gravitational potential energy, which converts to kinetic energy as it falls. Thus, a ball dropped from a height of 3.0 meters will have greater kinetic energy when it hits the ground than if it were dropped from a lower height.

Thank you for your patience, and I appreciate your understanding of the clarification.