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The stopping distance (s) of a car varies directly as the square of its speed (v). If a car traveling at 50 mph requires 170 ft...Asked by lakpa
The stopping distance s of a car varies directly as the square of its speed v. If a car traveling at 30 mph requires 81 ft to stop, find the stopping distance for a car traveling at 55 mph.
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Answered by
Steve
s = kv^2, so s/v^2 is constant. That means you want s where
s/55^2 = 81/30^2
s/55^2 = 81/30^2
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