Question

the steps for solving this equation using the quadratic formula . x ^ 2 + 3x - 4 = 0 FIRST STEP First Step : Identify a = 1 , b=3.c=-4; x = (- 3 + 5)/2 and x = (- 3 - 5)/2; x = (- 3 plus/minus sqrt(9 + 16))/2; x = (- 3 plus/minus sqrt(25))/2; x = (- 3 plus/minus sqrt((3) ^ 2 - 4(1)(- 4)))/(2(1)) x = 1 and x = - 4; x = (- 3 plus/minus 5)/2; x = 2/2 and x = - 8/2

Answer 1

The first step is to identify the values of a, b, and c in the quadratic equation. In this case, a = 1, b = 3, and c = -4.

Next, substitute these values into the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Plugging in the values, we get:

x = (-(3) ± √((3)^2 - 4(1)(-4))) / (2(1))

Simplify inside the square root:

x = (-3 ± √(9 + 16)) / 2

Combine like terms inside the square root:

x = (-3 ± √(25)) / 2

Since the square root of 25 is 5, we have:

x = (-3 ± 5) / 2

This gives us two possible solutions:

x = (-3 + 5) / 2 (which simplifies to x = 2/2)

x = (-3 - 5) / 2 (which simplifies to x = -8/2)