The standard molar entropy value of N2 (g) is 191.5 J/K-mol,

Question

of O2 (g) is 205.0 J/K-mol and of NO2 (g) is 240.0 J/K-mol. From these values
we can calculate the Delta S for the reaction N2 (g) + 2 O2 (g) produces 2 NO2 (g) to be

a. – 156.5 J/K
b. 636.5 J/K
c. 15.5 J/K
d. – 121.5 J/K
e. – 83.5 J/K

help

Answer 1

dSrxn = (n*dSo products) - (n*dSo reactants)

Answer 2

how do i set this up?

Answer 3

.........N2 + 2O2 ==> 2NO2
.......191.5..205.0...240

dSrxn = (n*products)-(n*reactants)
dSrxn = (2*240) -[(191.5+2(205)]

Answer 4

right.