The standard enthalpy of formation of Al3-(aq) is -538.4kJ/mol. How much heat is evolved when 0.3724 g of Al(s) reacts with excess hydrochloric acid?

Answer 1

0.3724 g x 26.98MW = 10.05 mol
-538.4kJ x 10.05 mol = -5410 kJ/mol
5410 kJ/mol of heat is evolved?????

Answer 2

Do you mean Al^3+ and not Al^3-?
moles = grams/molar mass not grams x molar mass.
You need to write and balance an equation, also.

Answer 3

yes, Al3+ sorry. so the moles=.01380. Could you help with the equation?