x and x+2
x^2 + (x+2)^2 = (2x+2)^2 - 48
x^2 + x^2 + 4 x + 4 = 4 x^2 + 8 x + 4 - 48
2 x^2 + 4 x - 48 = 0
x^2 + 2 x - 24 = 0
(x -4)(x+6) = 0
x = 4 and x+2 = 6
the square of the sum of two consecutive positive even integer is greater than the sum of their square by 48. Find two integers.
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