If the piston moves 0.500 cm = 5*10^-3 m, , a force of 5 N is applied to the piston.
The piston area is (pi/4)*(0.02)^2 = 3.14*10^-4 m^2
The pressure is then
5 N/(Piston Area, m^2) = ___ Pascals
Finally calculate the depth necessary to attain that gauge pressure.
The spring of the pressure gauge has a force constant of 1,000 N/m,and the piston has a diameter of 2.00 cm.when the gauge is lowered into water,at what depth does the piston move in by 0.500 cm?
1 answer
1 answer