the speed of an object at the end of 4 successive seconds is 20,25,30 and 35 meters per second,respectively.the acceleration of this object is?
4 answers
a = (V-Vo)/t = (25-20)/4 = 1.25 m/s^2.
what is the actual answer
V=20 m/s
T=4s
A=20/4
=5m/s2
For 25 m/s we know that in 1 second 5 m/s velocity increase for this case we will add 1 second in 4,
=25/5=5m/s2
Same case; 30 and 5seconds plus 1 second=6seconds
=30/6=5m/s2
For 35 we will ad 6+1=7 seconds
=35/7=5m/s2
Hence the over all resultant is 5 m/s2
Aijaz ali
T=4s
A=20/4
=5m/s2
For 25 m/s we know that in 1 second 5 m/s velocity increase for this case we will add 1 second in 4,
=25/5=5m/s2
Same case; 30 and 5seconds plus 1 second=6seconds
=30/6=5m/s2
For 35 we will ad 6+1=7 seconds
=35/7=5m/s2
Hence the over all resultant is 5 m/s2
Aijaz ali
Option A is correct
3 answers