The speed of an elevator (in feet per second) is modeled by the function f(x)=1.6875x , where x is time in seconds. Estimate the average rate of change between 3.9 seconds and 8.2 seconds. Round the final answer to two decimal places.(1 point)
Responses
about 6.75 feet/second
about 6.75 feet/second
about 4.00 feet/second
about 4.00 feet/second
about 1.69 feet/second
about 1.69 feet/second
about 0.59 feet/second
9 answers
about 1.69 feet/second
Estimate the average rate of change from when x=3.1 to when x=5.89 .
(1 point)
Responses
approximately −0.17
approximately negative 0.17
approximately 0.17
approximately 0.17
approximately 6
approximately 6
approximately 0.5
(1 point)
Responses
approximately −0.17
approximately negative 0.17
approximately 0.17
approximately 0.17
approximately 6
approximately 6
approximately 0.5
approximately 0.17
If the function g(x)=6x+2 models the number of leaves on a plant x weeks after being planted, which of the following accurately calculates the average rate of change in leaves between weeks 6 and 10?(1 point)
Responses
f(b)−f(a)b−a=62−3810−6=6 leaves
Start Fraction f left parenthesis b right parenthesis minus f left parenthesis a right parenthesis over b minus a End Fraction equals Start Fraction 62 minus 38 over 10 minus 6 End Fraction equals 6 leaves
f(b)+f(a)=62+38=100 leaves
f left parenthesis b right parenthesis plus f left parenthesis a right parenthesis equals 62 plus 38 equals 100 leaves
f(b)−f(a)b+a=62−3810+6=1.5 leaves
Start Fraction f left parenthesis b right parenthesis minus f left parenthesis a right parenthesis over b plus a End Fraction equals Start Fraction 62 minus 38 over 10 plus 6 End Fraction equals 1.5 leaves
f(b)+f(a)b−a=62+3810−6=25 leaves
Responses
f(b)−f(a)b−a=62−3810−6=6 leaves
Start Fraction f left parenthesis b right parenthesis minus f left parenthesis a right parenthesis over b minus a End Fraction equals Start Fraction 62 minus 38 over 10 minus 6 End Fraction equals 6 leaves
f(b)+f(a)=62+38=100 leaves
f left parenthesis b right parenthesis plus f left parenthesis a right parenthesis equals 62 plus 38 equals 100 leaves
f(b)−f(a)b+a=62−3810+6=1.5 leaves
Start Fraction f left parenthesis b right parenthesis minus f left parenthesis a right parenthesis over b plus a End Fraction equals Start Fraction 62 minus 38 over 10 plus 6 End Fraction equals 1.5 leaves
f(b)+f(a)b−a=62+3810−6=25 leaves
f(b)−f(a)b−a=62−3810−6=6 leaves
A helium balloon is at a height of 1,200 ft. after two minutes in flight. The balloon finally pops after seven minutes in flight, at a height of 10,500 ft. What is the average rate of change in height for the balloon over this period of time?(1 point)
Responses
1,033.33 ft./min.
1,033.33 ft./min.
9,300 ft./min.
9,300 ft./min.
2,340 ft./min.
2,340 ft./min.
1,860 ft./min.
Responses
1,033.33 ft./min.
1,033.33 ft./min.
9,300 ft./min.
9,300 ft./min.
2,340 ft./min.
2,340 ft./min.
1,860 ft./min.
1,860 ft./min.
An arcade manager finds that revenue, R, based on a per-game fee, f, for unlimited play can be modeled by the function R=−480f2+3,120f . Which of the following correctly interprets the average rate of change in revenue if the per-game fee increased from $1 to $3?(1 point)
Responses
The per-game fee would decrease by an average of $1,200 per $1 increase in the revenue.
The per-game fee would decrease by an average of $1,200 per $1 increase in the revenue.
The per-game fee would increase by an average of $1,200 per $1 increase in the revenue.
The per-game fee would increase by an average of $1,200 per $1 increase in the revenue.
Revenue would increase by an average of $1,200 per $1 increase in the per-game fee.
Revenue would increase by an average of $1,200 per $1 increase in the per-game fee.
Revenue would decrease by an average of $1,200 per $1 increase in the per-game fee.
Responses
The per-game fee would decrease by an average of $1,200 per $1 increase in the revenue.
The per-game fee would decrease by an average of $1,200 per $1 increase in the revenue.
The per-game fee would increase by an average of $1,200 per $1 increase in the revenue.
The per-game fee would increase by an average of $1,200 per $1 increase in the revenue.
Revenue would increase by an average of $1,200 per $1 increase in the per-game fee.
Revenue would increase by an average of $1,200 per $1 increase in the per-game fee.
Revenue would decrease by an average of $1,200 per $1 increase in the per-game fee.
Revenue would increase by an average of $1,200 per $1 increase in the per-game fee.
1 answer