the speed of a train is reduced uniformly from 10 m/s to 5 m/s while covering a distance of 150 m. What is the acceleration of the train? how much farther will it travel before coming to rest, assuming the same acceleration ?

Answer 1

Vo = 10 m/s.
V = 5 m/s.
d = 150 m.
a = ?

a. V^2 = Vo^2 + 2a*d
a = (V^2-Vo^2)/2d =

b. d = (V^2-Vo^2)/2a. V = 0, Vo = 5 m/s.

Answer 2

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