Increases ?? from 15 m/s to 6 m/s ???
anyway
a = (final velocity - initial velocity) / time
d = Vi t + (1/2) a t^2
= 15 (20) + (1/2) a (400)
the speed of a bus increase uniform from 15mls 6mls in 20s calculate.a the average speed.b accelaration. c the distance travelled during the either period
2 answers
Na bro it aint like dat
First subtract the distance (change in velocity)(6-15) , the question is not even correct cause it can't increase from 15 to 6 maybe he or she meant 60 so u subtract (60 from 15) then whatever u get divided by the time which is 20 sec that's how u get the answer for acceleration
First subtract the distance (change in velocity)(6-15) , the question is not even correct cause it can't increase from 15 to 6 maybe he or she meant 60 so u subtract (60 from 15) then whatever u get divided by the time which is 20 sec that's how u get the answer for acceleration