Let's denote the speed of Maluma's car as \( s \) miles per hour.
According to the problem, Sharice's car is traveling at 10 miles per hour slower than twice the speed of Maluma's car. Therefore, we can express Sharice's speed as: \[ \text{Sharice's speed} = 2s - 10 \]
We know that Sharice covers 93 miles in 1 hour and 30 minutes. Converting 1 hour and 30 minutes to hours, we have: \[ 1 \text{ hour} + 30 \text{ minutes} = 1 + \frac{30}{60} = 1.5 \text{ hours} \]
Now, we can find Sharice's speed using the formula \( \text{speed} = \frac{\text{distance}}{\text{time}} \): \[ \text{Sharice's speed} = \frac{93 \text{ miles}}{1.5 \text{ hours}} = 62 \text{ mph} \]
Now, we can set up the equation using the expression we have for Sharice's speed: \[ 2s - 10 = 62 \]
To find \( s \), we solve for it: \[ 2s = 62 + 10 \] \[ 2s = 72 \] \[ s = \frac{72}{2} = 36 \]
Thus, Maluma's speed is \( \boxed{36} \text{ mph} \).