Question

The specific heats (in units of J/g•K) of MoF6, CHBr3, and SnCl4 are 0.8090, 0.5172, and 0.6345,
respectively. What is the order of the molar heat capacities? Formula weights: MoF6 209.9; CHBr3 252.7; SnCl4
260.5
(a) MoF6>CHBr3>SnCl4 (b) MoF6>SnCl4>CHBr3 (c) CHBr3>MoF6>SnCl4
(d) CHBr3>SnCl4>MoF6 (e) SnCl4>MoF6>CHBr3
I thiink the answer is A b/c of the specific heats (if i convert to molar I still get A)
The standard heat of forrmation of 1-propanol cannot be measured directly but can be determined
indirectly from other heats of reaction by applying Hess’s Law. Given the following data for the combustion of
carbon, hydrogen, and 1-propanol, C3H8O, in oxygen:
C (s) + O2 (g) → CO2 (g) ∆H = -393.5 kJ
H2 (g) + 1
/2 O2 (g) → H2O (l) ∆H = -285.8 kJ
C3H8O + 4
1
/2 O2 (g) → 3 CO2 (g) + 4 H2O (l) ∆H = -2.011 x 103
kJ
So I got -2321.7kj/mol, would it be correct?
I appreciate any help!