The specific heat of liquid bromine is 0.226 J/(g•°C). How much heat (J) is required to raise the temperature of 31.2 g of bromine from 25.00°C to 27.30°C?

Group of answer choices

16.2

16.2 J

10.4 J

33.7

1 answer

10.4 J

To calculate the amount of heat required, you can use the formula:

Q = m * c * ∆T

Where:
Q = heat energy (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/(g•°C))
∆T = change in temperature (in °C)

Plugging in the values given:

Q = 31.2 g * 0.226 J/(g•°C) * (27.30°C - 25.00°C)
Q = 31.2 g * 0.226 J/(g•°C) * 2.30°C
Q = 10.4 J

Therefore, the amount of heat required to raise the temperature of 31.2 g of bromine from 25.00°C to 27.30°C is 10.4 J.