The sum of the heats gained is zero (some will lose heat and be negative).
Heatgainedcopper+heatgained water=0
33.6g*c*3.63-47=0
solve for c
The specific heat of copper metal was determined by putting a piece of the metal weighing 33.6 g in hot water. The quantity of heat absorbed by the metal was calculated to be 47 J from the temperature drop of the water. What was the specific heat of the metal if the temperature of the metal rose 3.63°C?
1 answer