The Spanish Club at Santa Fe Middle School wants to sell mini quiches to raise money for a field trip. The culinary department at their school will make the quiches for $30 plus $0.50 per quiche for the ingredients. The Spanish Club wants to sell each quiche for $2. How many quiches will they need to sell in order to break even?

Question

A. 75 quiches
B. 20 quiches
C. 12 quiches
D. 45 quiches

Answer 1

Let x be the number of quiches the Spanish Club needs to sell in order to break even.

Total cost = $30 + $0.50x
Total revenue = $2x

Break even when total revenue = total cost:

$2x = $30 + $0.50x
$1.50x = $30
x = 20

Therefore, the Spanish Club will need to sell 20 quiches in order to break even.

B. 20 quiches

Answer 2

The Baynard High School Boosters are selling hot dogs and pretzels at the concession stand. They have 300 hot dogs and pretzels in stock and want to earn an income of $800. They plan to sell the hot dogs for $4 each and the pretzels for $2 each. How many hot dogs and how many pretzels do the boosters need to sell to reach their goal of $800?

Answer 3

Let's represent the number of hot dogs as h and the number of pretzels as p.

The boosters want to earn a total income of $800, so the equation would be:
4h + 2p = 800

They have 300 hot dogs and pretzels in stock, so the total number of items would be:
h + p = 300

We can multiply the first equation by 2 and subtract it from the second equation to eliminate variable p:
2h + 2p = 600
4h + 2p = 800
---------------
2h = 200
h = 100

So, the boosters need to sell 100 hot dogs.
Now, substitute h = 100 into h + p = 300 to find p:
100 + p = 300
p = 200

Therefore, the boosters need to sell 100 hot dogs and 200 pretzels to reach their goal of $800.