a. if the shuttle were in orbit, the 2000kg will weigh zero.
b. Maybe the part a was not interested in weight at all, but the gravitational attracation
W=GMe*2000/(6.380+.4)^2
That is the graviataional attraction,perhaps that is what the teacher wanted in part a.
Then part b would be
g'*2000=W so g'=W/2000
c. g'=V^2/(6.38+.4)^2 solve for V
the space shuttle typically orbits 400 km above the earths surface. The earth has a mass of 5.98 * 10^24 kg and a radius of 6380km.
A) How much would a 2000 kg part for the space station weigh when it has been lifted to that orbit in the shuttles cargo bay?
B)Use your result from Part A to determine the acceleration due to gravity at that altitude.
C) Use your knowledge of circular motion to determine the orbital speed of the shuttles cargo.
2 answers
I erred on units.
W=GMe*2000/(6.380E6+.4E6)^2
g'=V^2/(6.38E6+.4E6)^2 solve for V
W=GMe*2000/(6.380E6+.4E6)^2
g'=V^2/(6.38E6+.4E6)^2 solve for V
0 answers