d = V*t = 1500m/s * 3.9s = 5850 m.=Total
distance traveled.
Depth = 5850/2 = 2925 m.
The sonar of a stationary ship sends a signal with a frequency of 5.0x103-Hz through water. If the signals speed is 1.5x103-m/s and the echoes detection is 3.9-sec later. What is the depth of the water under the ship?
1 answer