CO2 x (1 mol/22.4L) = 1.12 mols CO2.
NH3 x (1 mol/22.4L) = 0.89 mols NH3.
Therefore, NH3 is the limiting reagent and you will produce 0.89 mol NaHCO3. Convert that to grams.
The solvay process in an industrial method for preparing baking soda. In the process, CO2, NH3, H2O, and NaCl react to produce NaHCO3. If 25.0 L of carbon dioxide gas at STP and 20.0 L of ammonia gas at STP react in excess water and salt, what is the mass of baking soda produced ? The equation for the reaction is: CO2 (g) + NH3(g)+H2O(l)+NaCl(s)= NaHCO3(s)+NH4Cl(aq)
4 answers
0.89 mol NaHCO3* 84.01g = 74.8 g ?
For the following reaction, 0.431 moles of iron are mixed with 0.293 moles of oxygen gas.
iron (s) + oxygen (g) iron(II) oxide (s)
What is the FORMULA for the limiting reagent
iron (s) + oxygen (g) iron(II) oxide (s)
What is the FORMULA for the limiting reagent
75.0 g NaHCO3