The solution was created by dissolving .34 mol Na(OH) and 0.15 miles Ca(OH)2 in water. The final volume of the solution was 2.5 L. calculate the POH of the solution.

Answer 1

To find the pOH of the solution, we first need to calculate the concentration of hydroxide ions (OH-) in the solution.

For Na(OH):
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

0.34 mol NaOH x 40 g/mol = 13.6 g NaOH
1 L of solution with 13.6 g NaOH will have a concentration of 13.6 g/L = 0.136 g/L

For Ca(OH)2:
Molar mass of Ca(OH)2 = 40 + 2(16) + 2(1) = 74 g/mol

0.15 mol Ca(OH)2 x 74 g/mol = 11.1 g Ca(OH)2
1 L of solution with 11.1 g Ca(OH)2 will have a concentration of 11.1 g/L = 0.111 g/L

Total concentration of OH-:
0.136 g/L (from NaOH) + 0.111 g/L (from Ca(OH)2) = 0.247 g/L

Convert the concentration to mol/L:
0.247 g/L / 17 g/mol = 0.0145 mol/L

Calculate pOH:
pOH = -log[OH-] = -log(0.0145) = 1.84

Therefore, the pOH of the solution is 1.84.