To solve the equation \( 172 \cdot (2)^x = 272 \), start by isolating the exponential term.
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Divide both sides by 172: \[ (2)^x = \frac{272}{172} \]
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Simplifying the right side: \[ \frac{272}{172} = \frac{272 ÷ 172}{172 ÷ 172} = \frac{272 ÷ 172}{1} = \frac{4}{2.5} \text{ (this needs to be further simplified)} \] Alternatively, calculate \( \frac{272}{172} = \frac{272}{172} = \frac{68}{43} \):
\( 68 \div 4 = 17 \) and \( 43 \div 4 = 10.75. \)
Therefore \( = 1.2. \):
\( 2^x = 1.5 \):
Continuing the simplification, convert to a base of 2: \[ 2^x = 1.5 \]
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Express 1.5 as \( \frac{3}{2} \): \[ 2^x = \frac{3}{2} = \frac{3 \cdot 2^0}{2^1}. \]
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Take logarithms of both sides or observe if any integer solutions fit:
\[ x = 1 \Rightarrow 2^1 = 2. \] \[ x = 2 \Rightarrow 2^2 = 4. \] \[ x = 3 \Rightarrow 2^3 = 8. \]
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Look for integers above 3 to confirm:
\[ 4 \Rightarrow 2^4 = 16. \]
\[ 5 \Rightarrow 2^5 = 32. \]
To finalize check if estimate x through logarithms or other integers can confirm composed values. Based on integers possibilities, find x as:
After checking all integer values the valid solution exists. So the answer is:
The solution is x equals 5.