The solubility product of Mg(OH)2 is 1.2 x 10^-11. What minimum OH- concentration must be attained (for example, by adding NaOH) to decrease the Mg concentration in a solution of Mg(NO3)2 to less than 1.0 x 10^-10 M (molar)?

Question

The solubility product of Mg(OH)2 is 1.2 x 10^-11.  What minimum OH- concentration must be attained (for example, by adding NaOH) to decrease the Mg concentration in a solution of Mg(NO3)2 to less than 1.0 x 10^-10 M (molar)?

DrBob222 · Accepted Answer

Mg(OH)2 ==> Mg^+2 + 2OH^- Ksp = (Mg^+2)(OH^-)^2 = 1.2 x 10^-11 You know (Mg^+) and Ksp, solve for (OH^-). It's that simple.

Anonymous · Answer

0.109