The solubility product of Fe(OH)3 is 8.0x10^-40. Calculate its solubility at 35 degrees Celsius in a saturated solution.

Answer 1

IF Ksp is 8.0E-40 @ 35C, then, let S = solubility.
............Fe(OH)3 ==> Fe^+3 + 3OH^-
..............S.........S........3S

Ksp = (Fe^+3)(OH^-)^3
Ksp = (S)(3S)^3
Solve for S.