nFEo = RTlnK
You know n = 2, F = 96,485. solve for Eo, you know R = 8.314 and I assume T is 298 kelvin.
The solubility product for Ni(OH)2(s) is 1.6 ✕ 10−16. Calculate the value of ℰ° for the following half-reaction.
Ni(OH)2 + 2 e− → Ni + 2 OH −
I have no idea what equation to use or how to solve this problem
1 answer
1 answer