The solubility product expression for mercury(I) iodide, Hg2I2 is Ksp = ?

Question

My answer is [Hg2^2+^][2I^-^]^2^

Would you agree?

Answer 1

close.
Hg₂I₂ ==> Hg₂⁺⁺ + 2I^-

Ksp = [Hg₂^{++]2[I-]2
I hope that turns out ok. It's always so easy to miss turning that on or off. The ++ is the same as 2+}

Answer 2

See what I mean?
Ksp = [Hg₂⁺⁺]²[I^-]²
Let's see if this looks ok.

Answer 3

Still not right.
[Hg₂⁺⁺][I^-]²

Answer 4

That last one is ok.

Answer 5

Explain betterly

Answer 6

Hg2I2==>hg2^2+2I-.......coz Hg2^2 always exist in dimeric form

Answer 7

[hg2 ^2+] [I-]^2