The solubility of sodium selenate is 84 g/100 g of water at 35 oC. If a solution is obtained by dissolving 92 g of sodium selenate in 200 g of water at 35 oC, What do you call this solution?
(A) Diluted
(B) Saturated
(C) Unsaturated
(D) supersaturated
4 answers
92g/200 is the same as 46g/100. Since the solubility is 84/100, it certainly can't be saturated or supersaturated. So it must be .......
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