If solubility is 39 g/100 mL, how many grams will dissolve in 250 mL? That's
39 g x (250 mL/100 mL) = 97.5 g.
The problem states that 83 g has been dissolved; the solution can hold 97.5 so the solution is .......?
The solubility of NaCl at 17 celsisus degrees is 39 g per 100 ml water. If 83 g of NaCl is dissolved in 250ml of water at the same temperature, the resulting solution is: a)unsaturated; b)saturated; c)supersaturated
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