You are not given Ksp, That's what you are to calculate.
You have g/100 Cr(OH)3. Multiply by 10 gives you g/L. Divide by molar mass to get mols/L.
Then plug that into Ksp expression fopr (Cr^3+). That times 3 gives you the (OH^-). Then solve for Ksp. Post your work if you get stuck.
The solubility of Chromium (II) Hydroxide is .0035g/100mL
- Calculate the solubility product of Chromium (II) Hydroxide.
I know that we have to find Ksp. but i do not understand how to make the Ksp equation to calculate the solubility product, if it is already given to us...
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