If you had shown your work I could have found the error by now and both of us could move on.
CaSO4 ==> Ca^+2 + SO4^-2
Ksp = (Ca^+2)(SO2^-2)
I looked up the molar mass of CaSO4 and found 136.142 BUT you need to confirm that using values from your text/notes.
0.209 g CaSO4/100 mL = 2.09 g/L
2.09 g/L x (1 mole/136.142 g) = 0.01535 M
Then substitute that number into the Ksp expression I wrote above. The answer I obtained is 2.36E-4
The solubility of calcium sulfate at 30 degrees C is .209 g/100mL solution. Calculate its Ksp i calculated it and got 1.5 x 10 ^-2 but the program said that it was wrong if you could help explain how to do it i would appreciate it
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