To solve the problem, we can start by modeling the situation with the information provided.
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Set up the equation: From the information given, we know that the total amount collected is $800. The small vehicles are priced at $5 each and the large vehicles are priced at $10 each. The equation representing the total amount collected can be expressed as:
\[ 5x + 10y = 800 \]
Here, \(x\) represents the number of small vehicles and \(y\) represents the number of large vehicles.
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Determine the number of large vehicles: It is given that the soccer team washed 50 large vehicles, so we have:
\[ y = 50 \]
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Substitute the value of y into the equation: Now we can substitute 50 for \(y\) in the equation:
\[ 5x + 10(50) = 800 \]
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Calculate the amount collected from large vehicles:
\[ 5x + 500 = 800 \]
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Solve for x: Now, we can isolate \(x\):
\[ 5x = 800 - 500 \] \[ 5x = 300 \] \[ x = \frac{300}{5} \] \[ x = 60 \]
Therefore, the soccer team had to wash 60 small vehicles to meet their $800 total.
In summary, you have:
- Number of small vehicles \(x = 60\)
- Number of large vehicles \(y = 50\)
So, the completed responses are:
- \(x + 5y = 800\)
- Number of small vehicles = 60.