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The soccer team collected $800 at a car wash fundraiser. They charged $5 for small vehicles and $10 for larger vehicles. If x r...Asked by dee
The soccer team collected $1000 at a car wash fundraiser. They charged $5 for small vehicles and $10 for larger vehicles. If x represents the number of small cars and y represents the number of large cars, the amount collected cal be modeled by the equation: Response areax+Response areay=Response area.If the soccer team washed 75 large vehicles, that means they had to wash Response area small vehicles to meet their $1000 total.
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Answered by
GPT-4o mini
To solve the problem, we can set up an equation based on the information provided.
We know that:
- The charge for washing small vehicles (x) is $5.
- The charge for washing large vehicles (y) is $10.
- The total amount collected is $1000.
- The soccer team washed 75 large vehicles (y = 75).
Now, we can write the equation for the total amount collected:
\[ 5x + 10y = 1000 \]
Since \( y = 75 \), we can substitute \( y \) into the equation:
\[ 5x + 10(75) = 1000 \]
Calculating \( 10(75) \):
\[ 10(75) = 750 \]
Now, we can substitute this value back into the equation:
\[ 5x + 750 = 1000 \]
To isolate \( x \), we will subtract 750 from both sides:
\[ 5x = 1000 - 750 \]
\[ 5x = 250 \]
Now, divide both sides by 5:
\[ x = \frac{250}{5} \]
\[ x = 50 \]
So, the soccer team had to wash **50 small vehicles** to meet their $1000 total.
We know that:
- The charge for washing small vehicles (x) is $5.
- The charge for washing large vehicles (y) is $10.
- The total amount collected is $1000.
- The soccer team washed 75 large vehicles (y = 75).
Now, we can write the equation for the total amount collected:
\[ 5x + 10y = 1000 \]
Since \( y = 75 \), we can substitute \( y \) into the equation:
\[ 5x + 10(75) = 1000 \]
Calculating \( 10(75) \):
\[ 10(75) = 750 \]
Now, we can substitute this value back into the equation:
\[ 5x + 750 = 1000 \]
To isolate \( x \), we will subtract 750 from both sides:
\[ 5x = 1000 - 750 \]
\[ 5x = 250 \]
Now, divide both sides by 5:
\[ x = \frac{250}{5} \]
\[ x = 50 \]
So, the soccer team had to wash **50 small vehicles** to meet their $1000 total.
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