The so-called "liquidmetal" alloy has a yield strength of 1723 MPa and has a density of 6.1 grams per cubic centimetre. What is its specific yield strength in MPacm/gram?

1 answer

To find the specific yield strength of the "liquidmetal" alloy in units of MPa·cm/g, we need to divide the yield strength by the density in appropriate units.

  1. Convert the density from grams per cubic centimeter to kilograms per cubic meter: \[ 6.1 \text{ g/cm}^3 = 6.1 \times 10^3 \text{ kg/m}^3 \]

  2. Convert the density to grams per cubic centimeter to the desired unit: We can keep the density as 6.1 g/cm³ since we are interested in comparing in cm/g.

  3. Calculate the specific yield strength: The formula for specific yield strength is: \[ \text{Specific Yield Strength} = \frac{\text{Yield Strength}}{\text{Density}} \] where yield strength is given in MPa (which is equivalent to N/mm²) and density is in g/cm³:

    \[ \text{Specific Yield Strength} = \frac{1723 \text{ MPa}}{6.1 \text{ g/cm}^3} \]

  4. Perform the calculation: \[ \text{Specific Yield Strength} = \frac{1723}{6.1} \approx 282.2951 \text{ MPa·cm/g} \]

Thus, the specific yield strength of the liquidmetal alloy is approximately 282.3 MPa·cm/g.