well, we can find an approximation to h(4) by assuming that the tangent line at (5,3) stays close to the curve. So, assuming that you meant the slope is 7/(2t), h'(5) = 7/10
The tangent line is thus
7-3 = 7/10 (x-5)
now, plug in x=4 to approximate h(4)
If you meant h'(t) = (7/2)t, then make the appropriate adjustment
The slope of the tangent line to the graph of a function, h(t) is 7/2t
The function passes through the point (5,3)
Find h(4)
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