The slope of the line tangent to the curve xy+(y+1)^2=6 at the point (2, 1) is

Answer 1

the method

x dy + y dx+2(y+1)dy = 0
dy(x+2(y+1))=-ydx
dy/dx=slope= -y/(x+2(y+1))

so figure dy/dx at the given point

check my work.