The slope of a line is 15 and the point (3, -1) lies on the line. Write an equation of the line in point-slope form.

1 answer

The point-slope form of a line is given by the equation:

\[ y - y_1 = m(x - x_1) \]

where \( m \) is the slope, and \( (x_1, y_1) \) is a point on the line.

Given that the slope \( m \) is 15 and the point \( (3, -1) \) is on the line, we can substitute these values into the point-slope formula:

\[ y - (-1) = 15(x - 3) \]

This simplifies to:

\[ y + 1 = 15(x - 3) \]

Thus, the equation of the line in point-slope form is:

\[ y + 1 = 15(x - 3) \]