The slope field for a differential equation is shown in the figure. Determine the general solution of this equation.

The slope field has positive slopes in quadrants 2 and 4 and negative slopes in quadrants 1 and 4. It looks like a circle and at (0,0) it appears to have a slope of 1.

y=Cx2
x=Cy2
y2 – x2 = C2
x2 + y2 = C2

3 answers

If the slopes look like a circle, then it's a circle.
Note that for x^2+y^2 = 1
dy/dx = -x/y

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