The size of a parcel despatched through the post used to be limited by the fact that the sum of its length and girth (perimeter of the cross section) must not exceed 6 feet. What was the volume of the largest parcel of square cross- section which was acceptable for posting? (Let the cross-section be a square of side x feet.)

asked by Anonymous

8 years ago

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1 answer

v = x^2y
4x+y <= 6

see where that takes you.

answered by Steve

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Question

The size of a parcel despatched through the post used to be limited by the fact that the sum of its length and girth (perimeter of the cross section) must not exceed 6 feet. What was the volume of the largest parcel of square cross- section which was acceptable for posting? (Let the cross-section be a square of side x feet.)

1 answer

v = x^2y
4x+y <= 6

see where that takes you.

Ask a New Question or answer this question.

Steve · Answer

v = x^2y 4x+y <= 6 see where that takes you.