The simplified form of the complex no. (1-i/2 2i) (1/-2-2i) is.....?

Answer 1

(1-i)/(2-2i) = 1/2, so I assume we have

(1-i)/(2+2i) * 1/(-2-2i)
= (1-i)/(2+2i) * -1/(2+2i)
= -(1-i)/(2+2i)^2
= -(1-i)/(8i)
= -1/8 (1/i - 1)
= -1/8 (-1 - i)
= 1/8 + 1/8 i