The sides of a triangular path measure 7 m, 9 m, and 11 m. Find the perimeter of a similar triangle in which the shortest side has a length of 21 meters.(1 point)

Responses

33 m
33 m

81 m
81 m

21 m
21 m

27 m

1 answer

To find the perimeter of a similar triangle when the shortest side measures 21 meters, we first need to determine the ratio of similarity between the triangles.

The shortest side of the original triangle is 7 meters, and the shortest side of the similar triangle is 21 meters.

The ratio of the sides is given by:

\[ \text{Ratio} = \frac{\text{Shorter side of similar triangle}}{\text{Shorter side of original triangle}} = \frac{21 \text{ m}}{7 \text{ m}} = 3 \]

In a similar triangle, all sides are scaled by the same ratio. Therefore, we can find the lengths of the other two sides of the similar triangle:

  • The second side (originally 9 m):

\[ 9 \text{ m} \times 3 = 27 \text{ m} \]

  • The third side (originally 11 m):

\[ 11 \text{ m} \times 3 = 33 \text{ m} \]

Now, we can find the perimeter of the similar triangle by adding all the sides together:

\[ \text{Perimeter} = 21 \text{ m} + 27 \text{ m} + 33 \text{ m} = 81 \text{ m} \]

Thus, the perimeter of the similar triangle is 81 m.