The sides of a triangular path measure 7 m, 9 m, and 11 m. Find the perimeter of a similar triangle in which the shortest side has a length of 21 meters. (1 point)

Question

0.21 m

O 27 m

81 m

33 m

Answer 1

To find the perimeter of the similar triangle, we need to find the ratio of the corresponding sides.

The ratio between the shortest side of the original triangle (7m) and the shortest side of the similar triangle (21m) is 21m/7m = 3.

Since the sides of similar triangles are proportional, the ratio of the perimeter of the original triangle to the perimeter of the similar triangle will also be 3.

Therefore, the perimeter of the similar triangle can be found by multiplying the perimeter of the original triangle by 3.

Perimeter of the original triangle = 7m + 9m + 11m = 27m.

Perimeter of the similar triangle = 3 * 27m = 81m.

Therefore, the answer is 81m.