x + x+1 + x+2 = 126
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the sides of a triangle are consecutive integers.If its perimeter is 126cm.find the lengths of the sides.
3 answers
126cm = x + x + 1 + x + 2
126 = 3x + 3
126 – 3 = 3x
123 = 3x
123/3 = 3x/3
41 = x
The 3 consecutive sides of a triangle is 41,42 and 43.
126 = 3x + 3
126 – 3 = 3x
123 = 3x
123/3 = 3x/3
41 = x
The 3 consecutive sides of a triangle is 41,42 and 43.
126cm = x + x + 1 + x + 2
126 = 3x + 3
126 – 3 = 3x
123 = 3x
123/3 = 3x/3
41 = x
The 3 consecutive sides of a triangle are 41,42 and 43.
126 = 3x + 3
126 – 3 = 3x
123 = 3x
123/3 = 3x/3
41 = x
The 3 consecutive sides of a triangle are 41,42 and 43.