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The senior class at Hartford High School is planning their prom. They’ve narrowed the location down to two choices. The Regal Hotel charges, C , $500 for the ballroom rental fee and $75 per student, s , for the meal. The Greenhill Country Club charges, C , $1,000 for the ballroom rental fee and $65 per student, s , for the meal. Create a pair of linear equations that represent this real-world problem.(1 point)

Responses

Regal Hotel: C=1,000s+75; Greenhill Country Club: C=500s+65
Regal Hotel: upper C equals 1,000 s plus 75 ; Greenhill Country Club: upper C equals 500 s plus 65

Regal Hotel: C=75s+500; Greenhill Country Club: C=65s+1,000
Regal Hotel: upper C equals 75 s plus 500 ; Greenhill Country Club: upper C equals 65 s plus 1,000

Regal Hotel: C=500s+75; Greenhill Country Club: C=1,000s+65
Regal Hotel: upper C equals 500 s plus 75 ; Greenhill Country Club: upper C equals 1,000 s plus 65

Regal Hotel: C=75s+1,000; Greenhill Country Club: C=65s+500

1 answer

To create a pair of linear equations for the costs associated with the Regal Hotel and the Greenhill Country Club for the prom, we can define \( C \) as the total cost and \( s \) as the number of students.

  1. Regal Hotel:

    • The ballroom rental fee is $500.
    • The meal cost is $75 per student.
    • Therefore, the equation is: \[ C = 75s + 500 \]

  2. Greenhill Country Club:

    • The ballroom rental fee is $1,000.
    • The meal cost is $65 per student.
    • Therefore, the equation is: \[ C = 65s + 1000 \]

So, the correct response that represents this real-world problem is:

Regal Hotel: \( C = 75s + 500 \); Greenhill Country Club: \( C = 65s + 1,000 \)