The second term of a geometric progression is 12 more than the first term given that the common the ratio is half of the first term. Find the third term of the Geometric progression

4 answers

Solution.Tn=ar'n-1 where n=3

ar = 12 + a (i)
ar^2 = x (ii)
subtract equ (i) from equ (ii)
a = 6
substituting a = 6 into equ (i)
ar = 12 + a
6r = 12 + 6=18
r = 3.
ar'2 = 6 * 3'2
ar'2 = 54

65

ar'2=54

Ask a New Question or answer this question.

Similar Questions

The sum of the 3 terms in arithmetic sequence is 39.if these numbers is increased by 1,5 and 12 respectively the numbers would
1. 1 answer
a geometric progression has a third term of 20 and a sum to infinity which is three times the first term. find the first term
1. 1 answer
A Geometric progression X has a first term of 4a and its sixth term is 256. Another Geometric progression Y has a first term of
1. 11 answers
The second and fifth terms of a geometric progression(G.P. ) are 1 and 1/8 respectively find the first term and eight term.
1. 3 answers