the second rate superhero and his arch enemy, Melvin the minor menace, started 700 miles apart and flew straight toward each other in their jet propulsion packs. It took 5 hours for the two to meet. If the superhero's speed was 10mph slower than the menace's, what was the menace's speed?

Answer 1

Let's assume the menace's speed is represented by x mph.
Therefore, the superhero's speed is x - 10 mph.

We know that the total time it took for them to meet was 5 hours. Since the two were flying directly towards each other, their distances traveled would add up to 700 miles.

Using the formula: distance = speed × time, we can write two equations to represent their distances:

Distance traveled by the menace: x mph * 5 hours = 5x miles
Distance traveled by the superhero: (x - 10) mph * 5 hours = 5(x - 10) miles

Adding up their distances will give us the total distance of 700 miles, so:
5x + 5(x - 10) = 700

Simplifying the equation:
5x + 5x - 50 = 700
10x - 50 = 700
10x = 750
x = 75

Therefore, the menace's speed was 75 mph.