t2 = a + d = 2
t9 = a + 8d = 30
subtract them
7x = 28
d = 4
in a+d=2
a + 4 = 2
a = -2
t15 = a + 14d = -2 + 14(4) = 54
The second and ninth terms of an arithmetic sequence are 2 and 30 respectively. What is the fiftieth term.
2 answers
It is the fiftieth term not the fifteenth so would it be t50=a+49d
32 answers