To determine the mean score for Group B, we can use the information provided about the overall mean score for the entire class and the mean score for Group A.
- The total number of students in the class is 30, which means each group (Group A and Group B) contains 15 students.
- The mean score for Group A is 91%. Therefore, the total score for Group A can be calculated as follows: \[ \text{Total score for Group A} = \text{Mean score} \times \text{Number of students} = 91% \times 15 = 1365% \]
- The mean score for the entire class is 88%. Thus, the total score for the entire class is: \[ \text{Total score for the class} = \text{Mean score} \times \text{Number of students} = 88% \times 30 = 2640% \]
- Now, we can find the total score for Group B. Since the total score for the entire class is the sum of the total scores for both groups, we have: \[ \text{Total score for Group B} = \text{Total score for the class} - \text{Total score for Group A} = 2640% - 1365% = 1275% \]
- Now, we can calculate the mean score for Group B: \[ \text{Mean score for Group B} = \frac{\text{Total score for Group B}}{\text{Number of students in Group B}} = \frac{1275%}{15} = 85% \]
Thus, Group B has a mean score of 85%.
Since the mean score of Group B (85%) is lower than the mean score for the entire class (88%), we can conclude that:
The mean score for Group B will be lower than the mean score for the entire class.
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