12a + 4s = 188
6a + 9s = 171
12a = 188 - 4s
3a = 47 - s
Substitute s-value for a-value in second equation.
2(47 - s) + 9s = 171
Solve for s. Put that value in the first equation to find a. Put both into the second equation to check.
I'll let you do the calculations. I hope this helps.
The school that Trevon goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold 12 adult tickets and 4 student tickets for a total of $188. The school took in $171 on the second day by selling 6 adult tickets and 9 student tickets. What is the price each of one adult ticket and student ticket?
1 answer