The school band bought a saxophone and a clarinet for 3314 $ the saxophone cost 2276$ more than a clarinet what did each item cost ?

Answer 1

Let's call the cost of the clarinet C.

According to the information given, the cost of the saxophone is 2276$ more than the cost of the clarinet. So the cost of the saxophone is C + 2276$.

The total cost of the saxophone and the clarinet is 3314$. So we can write the equation:

C + (C + 2276$) = 3314$

Combining like terms:

2C + 2276$ = 3314$

Subtract 2276$ from both sides:

2C = 1038$

Divide both sides by 2:

C = 519$

So the cost of the clarinet is 519$.

To find the cost of the saxophone, we can substitute this value back into one of the equations above:

Cost of the saxophone = 519$ + 2276$

= 2795$

Therefore, the clarinet cost 519$ and the saxophone cost 2795$.